sbv-3.1: Data/SBV/Examples/Uninterpreted/Sort.hs
-----------------------------------------------------------------------------
-- |
-- Module : Data.SBV.Examples.Uninterpreted.Sort
-- Copyright : (c) Levent Erkok
-- License : BSD3
-- Maintainer : erkokl@gmail.com
-- Stability : experimental
--
-- Demonstrates uninterpreted sorts, together with axioms.
-----------------------------------------------------------------------------
{-# LANGUAGE DeriveDataTypeable #-}
module Data.SBV.Examples.Uninterpreted.Sort where
import Data.Generics
import Data.SBV
-- | A new data-type that we expect to use in an uninterpreted fashion
-- in the backend SMT solver. Note the custom @deriving@ clause, which
-- takes care of most of the boilerplate.
data Q = Q deriving (Eq, Ord, Data, Typeable)
-- | We need 'SymWord' and 'HasKind' instances, but default definitions
-- are always sufficient for uninterpreted sorts, so all we do is to
-- declare them as such. Note that, starting with GHC 7.6.1, we will
-- be able to simply derive these classes as well. (See <http://hackage.haskell.org/trac/ghc/ticket/5462>.)
instance SymWord Q
-- | 'HasKind' instance is again straightforward, no specific implementation needed.
instance HasKind Q
-- | Declare an uninterpreted function that works over Q's
f :: SBV Q -> SBV Q
f = uninterpret "f"
-- | A satisfiable example, stating that there is an element of the domain
-- 'Q' such that 'f' returns a different element. Note that this is valid only
-- when the domain 'Q' has at least two elements. We have:
--
-- >>> t1
-- Satisfiable. Model:
-- x = Q!val!0 :: Q
t1 :: IO SatResult
t1 = sat $ do x <- free "x"
return $ f x ./= x
-- | This is a variant on the first example, except we also add an axiom
-- for the sort, stating that the domain 'Q' has only one element. In this case
-- the problem naturally becomes unsat. We have:
--
-- >>> t2
-- Unsatisfiable
t2 :: IO SatResult
t2 = sat $ do x <- free "x"
addAxiom "Q" ["(assert (forall ((x Q) (y Q)) (= x y)))"]
return $ f x ./= x