answers-a-symbol-nobody-has-worked-out.yaml

# SPDX-FileCopyrightText: Copyright (c) 2025 Objectionary.com
# SPDX-License-Identifier: MIT
---
# yamllint disable rule:line-length
# One firing, and nothing is computed: the operands come down to the numbers
# they are, and what the entry answers with is a number standing for a sum
# nobody has worked out.
symbolic: |
  - λ: L_number_plus
    dataize:
      𝛿1: $.ρ
      𝛿2: $.x
    𝑛: Φ.number( φ ↦ ⟦ λ ⤍ 𝜎 ⟧ )
location: 'Q.@'
deep: true
input: >
  ⟦ bytes(φ) ↦ ⟦⟧,
    number(φ) ↦ ⟦ plus(ρ, x) ↦ ⟦ λ ⤍ L_number_plus ⟧ ⟧,
    @ ↦ 5.plus( 6 ) ⟧
result: '⟦ φ ↦ 𝜎1:λ, plus(x) ↦ L_number_plus:λ ⟧'
protocol: |
  𝕄(Φ.φ):
    𝑛·0·1 := 5
    𝑛·0·2 := 𝑛·0·1.plus( x ↦ 6 )
    𝕄(Φ.φ.x):
      𝑛·0·3 := Φ.bytes( φ ↦ 40-18-00-00-00-00-00-00:Δ )
      𝑛·0·4 := Φ.number( φ ↦ 𝑛·0·3 )
    𝔼(L_number_plus):
      𝔻(Φ.a🌵0):
        𝕄(Φ.a🌵0):
          𝑛·1·1 := 5
          𝑛·1·2 := Φ.bytes( φ ↦ 40-14-00-00-00-00-00-00:Δ )
        𝛿·1·1 := 40-14-00-00-00-00-00-00  # 5.0
      𝛿1·1 := 𝛿·1·1  # 𝔻(ξ.ρ)
      𝔻(Φ.a🌵1):
        𝕄(Φ.a🌵1):
          𝑛·1·3 := Φ.number( φ ↦ 𝑛·0·3 )
          𝑛·1·4 := Φ.bytes( φ ↦ 40-18-00-00-00-00-00-00:Δ )
        𝛿·1·2 := 40-18-00-00-00-00-00-00  # 6.0
      𝛿2·1 := 𝛿·1·2  # 𝔻(ξ.x)
      𝑛·1·5 := Φ.number( φ ↦ 𝜎1:λ )  # 𝑛
      𝕄(𝑛·1·5):
        𝑛·1·6 := Φ.number( φ ↦ 𝜎1:λ )
      𝑛·1·7 := 𝑛·1·6  # 𝕄(𝑛·1·5)