linear-base-0.8.1: examples/Foreign/List.hs
{-# LANGUAGE BangPatterns #-}
{-# LANGUAGE FlexibleInstances #-}
{-# LANGUAGE LinearTypes #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE TypeFamilies #-}
{-# LANGUAGE UndecidableInstances #-}
{-# LANGUAGE NoImplicitPrelude #-}
module Foreign.List where
import qualified Data.List as List
import Foreign.Marshal.Pure (Box, Pool)
import qualified Foreign.Marshal.Pure as Manual
import Prelude.Linear hiding (foldl, foldr, map)
-- XXX: we keep the last Cons in Memory here. A better approach would be to
-- always keep a Box instead.
data List a
= Nil
| Cons !a !(Box (List a))
-- TODO: generating appropriate instances using the Generic framework
instance
(Manual.Representable a) =>
Manual.MkRepresentable (List a) (Maybe (a, Box (List a)))
where
toRepr Nil = Nothing
toRepr (Cons a l) = Just (a, l)
ofRepr Nothing = Nil
ofRepr (Just (a, l)) = Cons a l
instance (Manual.Representable a) => Manual.Representable (List a) where
type AsKnown (List a) = Manual.AsKnown (Maybe (a, Box (List a)))
-- Remark: this is a bit wasteful, we could implement an allocation-free map by
-- reusing the old pointer with realloc.
--
-- XXX: the mapped function should be of type (a %1-> Pool %1-> b)
--
-- Remark: map could be tail-recursive in destination-passing style
map :: forall a b. (Manual.Representable a, Manual.Representable b) => (a %1 -> b) -> List a %1 -> Pool %1 -> List b
map _f Nil pool = pool `lseq` Nil
map f (Cons a l) pool =
withPools (dup pool) a (Manual.deconstruct l)
where
withPools :: (Pool, Pool) %1 -> a %1 -> List a %1 -> List b
withPools (pool1, pool2) a' l' =
Cons (f a') (Manual.alloc (map f l' pool1) pool2)
foldr :: forall a b. (Manual.Representable a) => (a %1 -> b %1 -> b) -> b %1 -> List a %1 -> b
foldr _f seed Nil = seed
foldr f seed (Cons a l) = f a (foldr f seed (Manual.deconstruct l))
foldl :: forall a b. (Manual.Representable a) => (b %1 -> a %1 -> b) -> b %1 -> List a %1 -> b
foldl _f seed Nil = seed
foldl f seed (Cons a l) = foldl f (f seed a) (Manual.deconstruct l)
-- Remark: could be tail-recursive with destination-passing style
-- | Make a 'List' from a stream. 'List' is a type of strict lists, therefore
-- the stream must terminate otherwise 'unfold' will loop. Not tail-recursive.
unfold :: forall a s. (Manual.Representable a) => (s -> Maybe (a, s)) -> s -> Pool %1 -> List a
unfold step state pool = dispatch (step state) (dup pool)
where
-- XXX: ^ The reason why we need to `dup` the pool before we know whether the
-- next step is a `Nothing` (in which case we don't need the pool at all) or a
-- `Just`, is because of the limitation of `case` to the unrestricted
-- case. Will be fixed.
dispatch :: Maybe (a, s) -> (Pool, Pool) %1 -> List a
dispatch Nothing pools = pools `lseq` Nil
dispatch (Just (a, next)) (pool1, pool2) =
Cons a (Manual.alloc (unfold step next pool1) pool2)
-- | Linear variant of 'unfold'. Note how they are implemented exactly
-- identically. They could be merged if multiplicity polymorphism was supported.
unfoldL :: forall a s. (Manual.Representable a) => (s %1 -> Maybe (a, s)) -> s %1 -> Pool %1 -> List a
unfoldL step state pool = dispatch (step state) (dup pool)
where
dispatch :: Maybe (a, s) %1 -> (Pool, Pool) %1 -> List a
dispatch Nothing pools = pools `lseq` Nil
dispatch (Just (a, next)) (pool1, pool2) =
Cons a (Manual.alloc (unfoldL step next pool1) pool2)
ofList :: (Manual.Representable a) => [a] -> Pool %1 -> List a
ofList l pool = unfold List.uncons l pool
toList :: (Manual.Representable a) => List a %1 -> [a]
toList l = foldr (:) [] l
-- | Like unfold but builds the list in reverse, and tail recursive
runfold :: forall a s. (Manual.Representable a) => (s -> Maybe (a, s)) -> s -> Pool %1 -> List a
runfold step state pool = loop state Nil pool
where
loop :: s -> List a %1 -> Pool %1 -> List a
loop state' acc pool' = dispatch (step state') acc (dup pool')
dispatch :: Maybe (a, s) -> List a %1 -> (Pool, Pool) %1 -> List a
dispatch Nothing !acc pools = pools `lseq` acc
dispatch (Just (a, next)) !acc (pool1, pool2) =
loop next (Cons a (Manual.alloc acc pool1)) pool2
ofRList :: (Manual.Representable a) => [a] -> Pool %1 -> List a
ofRList l pool = runfold List.uncons l pool