implicit-0.2.0: Graphics/Implicit/Export/MarchingSquaresFill.hs
-- Implicit CAD. Copyright (C) 2011, Christopher Olah (chris@colah.ca)
-- Copyright (C) 2016, Julia Longtin (julial@turinglace.com)
-- Released under the GNU AGPLV3+, see LICENSE
-- Allow us to use explicit foralls when writing function type declarations.
{-# LANGUAGE ExplicitForAll #-}
-- export getContourMesh, which returns an array of triangles describing the interior of a 2D object.
module Graphics.Implicit.Export.MarchingSquaresFill (getContourMesh) where
import Prelude(Bool(True, False), fromIntegral, ($), (-), (+), (/), (*), (<=), (>), ceiling, concat, max, div)
import Graphics.Implicit.Definitions (ℕ, ℝ2, Polytri, Obj2, (⋯/), (⋯*))
import Data.VectorSpace ((^-^),(^+^))
-- Each step on the Y axis is done in parallel using Control.Parallel.Strategies
import Control.Parallel.Strategies (using, rdeepseq, parBuffer)
-- apply a function to both items in the provided tuple.
both :: forall t b. (t -> b) -> (t, t) -> (b, b)
both f (x,y) = (f x, f y)
getContourMesh :: ℝ2 -> ℝ2 -> ℝ2 -> Obj2 -> [Polytri]
getContourMesh p1 p2 res obj =
let
-- How much space are we rendering?
d = p2 ^-^ p1
-- How many steps will we take on each axis?
nx :: ℕ
ny :: ℕ
n@(nx,ny) = (ceiling) `both` (d ⋯/ res)
-- a helper for calculating a position inside of the space.
gridPos :: (ℕ,ℕ) -> (ℕ,ℕ) -> ℝ2
gridPos n' m = p1 ^+^ d ⋯* ((fromIntegral `both` m) ⋯/ (fromIntegral `both` n'))
-- compute the triangles.
trisOnGrid :: [[[Polytri]]]
trisOnGrid = [[getSquareTriangles (gridPos n (mx,my)) (gridPos n (mx+1,my+1)) obj
| mx <- [0.. nx-1] ] | my <- [0..ny-1] ] `using` parBuffer (max 1 $ fromIntegral $ div ny 32) rdeepseq
triangles = concat $ concat trisOnGrid
in
triangles
-- | This function gives line segments to divide negative interior
-- regions and positive exterior ones inside a square, based on its
-- values at its vertices.
-- It is based on the linearly-interpolated marching squares algorithm.
getSquareTriangles :: ℝ2 -> ℝ2 -> Obj2 -> [Polytri]
getSquareTriangles (x1, y1) (x2, y2) obj =
let
(x,y) = (x1, y1)
-- Let's evaluate obj at four corners...
x1y1 = obj (x1, y1)
x2y1 = obj (x2, y1)
x1y2 = obj (x1, y2)
x2y2 = obj (x2, y2)
-- And the center point..
c = obj ((x1+x2)/2, (y1+y2)/2)
dx = x2 - x1
dy = y2 - y1
-- linearly interpolated midpoints on the relevant axis
-- midy2
-- _________*_________
-- | |
-- | |
-- | |
--midx1* * midx2
-- | |
-- | |
-- | |
-- ---------*---------
-- midy1
midx1 = (x, y + dy*x1y1/(x1y1-x1y2))
midx2 = (x + dx, y + dy*x2y1/(x2y1-x2y2))
midy1 = (x + dx*x1y1/(x1y1-x2y1), y )
midy2 = (x + dx*x1y2/(x1y2-x2y2), y + dy)
-- decompose a square into two triangles...
square :: forall t t1. t -> t1 -> t1 -> t1 -> [(t, t1, t1)]
square aa bb cc dd = [(aa,bb,cc), (aa,cc,dd)]
in case (x1y2 <= 0, x2y2 <= 0,
x1y1 <= 0, x2y1 <= 0) of
-- Yes, there's some symetries that could reduce the amount of code...
-- But I don't think they're worth exploiting...
(True, True,
True, True) -> square (x1,y1) (x2,y1) (x2,y2) (x1,y2)
(False, False,
False, False) -> []
(True, True,
False, False) -> square midx1 midx2 (x2,y2) (x1,y2)
(False, False,
True, True) -> square (x1,y1) (x2,y1) midx2 midx1
(False, True,
False, True) -> square midy1 (x2,y1) (x2,y2) midy2
(True, False,
True, False) -> square (x1,y1) midy1 midy2 (x1,y2)
(True, False,
False, False) -> [((x1,y2), midx1, midy2)]
(False, True,
True, True) ->
[(midx1, (x1,y1), midy2), ((x1,y1), (x2,y1), midy2), (midy2, (x2,y1), (x2,y2))]
(True, True,
False, True) ->
[((x1,y2), midx1, (x2,y2)), (midx1, midy1, (x2,y2)), ((x2,y2), midy1, (x2,y1))]
(False, False,
True, False) -> [(midx1, (x1,y1), midy1)]
(True, True,
True, False) ->
[(midy1,midx2,(x2,y2)), ((x2,y2), (x1,y2), midy1), (midy1, (x1,y2), (x1,y1))]
(False, False,
False, True) -> [(midx2, midy1, (x2,y1))]
(True, False,
True, True) ->
[(midy2, (x2,y1), midx2), ((x2,y1), midy2, (x1,y1)), ((x1,y1), midy2, (x1,y2))]
(False, True,
False, False) -> [(midx2, (x2,y2), midy2)]
(True, False,
False, True) -> if c > 0
then [((x1,y2), midx1, midy2), ((x2,y1), midy1, midx2)] --[[midx1, midy2], [midx2, midy1]]
else [] --[[midx1, midy1], [midx2, midy2]]
(False, True,
True, False) -> if c <= 0
then [] --[[midx1, midy2], [midx2, midy1]]
else [((x1,y1), midy1, midx1), ((x2,y2), midx2, midy2)] --[[midx1, midy1], [midx2, midy2]]