haskell-tools-refactor-1.0.1.1: examples/Expr/LambdaCase.hs
{-# LANGUAGE LambdaCase, EmptyCase #-}
module Expr.LambdaCase where
a = \case 1 -> 0
_ -> 1
b = \case { 1 -> 0; _ -> 1 }
c = \case {}
d = \case{-# LANGUAGE LambdaCase, EmptyCase #-}
module Expr.LambdaCase where
a = \case 1 -> 0
_ -> 1
b = \case { 1 -> 0; _ -> 1 }
c = \case {}
d = \case