haskell-tools-refactor-1.0.1.1: examples/Expr/Case.hs
module Expr.Case where
x = 12
a = case x of 1 -> 0
_ -> 1
b = case x of { 1 -> 0; _ -> 1 }
module Expr.Case where
x = 12
a = case x of 1 -> 0
_ -> 1
b = case x of { 1 -> 0; _ -> 1 }