packages feed

haskell-src-meta-0.5: examples/SKI.hs

{-# LANGUAGE DeriveDataTypeable, PatternGuards, TemplateHaskell #-}

module Language.Haskell.Meta.QQ.SKI (SKI(..),ski) where

import Language.Haskell.Meta (parseExp, parsePat)
import Language.Haskell.TH.Lib
import Language.Haskell.TH.Ppr
import Language.Haskell.TH.Quote
import Language.Haskell.TH.Syntax
import Language.Haskell.Meta.Utils (cleanNames, ppDoc, unQ)
import Text.ParserCombinators.ReadP
import Data.Typeable(Typeable)
import Data.Generics(Data)
import Text.PrettyPrint(render)

data SKI = S | K | I | E Exp | SKI :$ SKI
  deriving (Eq,Data,Typeable)

run :: String -> [SKI]
run = fmap eval . fst . parse

-- I x = x
-- K x y = x
-- S x y z = (x z) (y z)
eval :: SKI -> SKI
eval (I :$ x)               = eval x
eval ((K :$ x) :$ y)        = eval x
eval (((S :$ x) :$ y :$ z)) = eval (eval (x :$ z) :$ eval (y :$ z))
eval (E e :$ E e')          = E (unQ[|$(return e) $(return e')|])
eval (x :$ y)               = eval0 ((eval x) :$ (eval y))
eval  x                     = x
eval0 (I :$ x)               = eval x
eval0 ((K :$ x) :$ y)        = eval x
eval0 (((S :$ x) :$ y :$ z)) = eval (eval (x :$ z) :$ eval (y :$ z))
eval0 (E e :$ E e')          = E (unQ[|$(return e) $(return e')|])
eval0  x                     = x

ski :: QuasiQuoter
ski = QuasiQuoter
        {quoteExp = skiExpQ
        ,quotePat = skiPatQ}

instance Lift SKI where
  lift = liftSKI

liftSKI (E e) = return e
liftSKI a     = go a
  where go S = [|S|]
        go K = [|K|]
        go I = [|I|]
        go (E e) = [|E e|]
        go (x:$y) = [|$(go x) :$ $(go y)|]

instance Show SKI where
        showsPrec p (S) = showString "S"
        showsPrec p (K) = showString "K"
        showsPrec p (I) = showString "I"
        showsPrec p (E x1)
          = showParen (p > 10)
              (showString (render (ppDoc x1)))
        showsPrec p ((:$) x1 x2)
          = showParen (p > 10)
              (showsPrec 11 x1 . (showString " :$ " . showsPrec 10 x2))

skiExpQ :: String -> ExpQ
skiExpQ s = case run s of
              [] -> fail "ski: parse error"
              e:_ -> lift (cleanNames e)

skiPatQ :: String -> PatQ
skiPatQ s = do
  e <- skiExpQ s
  let p = (parsePat
            . pprint
              . cleanNames) e
  case p of
    Left e -> fail e
    Right p -> return p

-- ghci> parse "S(SS)IK(SK)"
-- ([(((S :$ (S :$ S)) :$ I) :$ K) :$ (S :$ K)],"")
parse :: String -> ([SKI], String)
parse = runP skiP

skiP :: ReadP SKI
skiP = nestedP parensP
  (let go a = (do b <- lexemeP (oneP <++ skiP)
                  go (a:$b)) <++ return a
    in lexemeP (go =<< lexemeP oneP))

oneP :: ReadP SKI
oneP = nestedP parensP
  (lexemeP (choice [sP
                   ,kP
                   ,iP
                   ,spliceP =<< look
                   ]))

spliceP :: String -> ReadP SKI
spliceP s
  | '[':s <- s = skip 1 >> go 1 [] s
  | otherwise  = pfail
  where go _ _   []         = pfail
        go 1 acc (']':_) = do skip (1 + length acc)
                              either (const pfail)
                                     (return . E)
                                     (parseExp (reverse acc))
        go n acc ('[':s)     = go (n+1) ('[':acc) s
        go n acc (']':s)     = go (n-1) (']':acc) s
        go n acc (c:s)       = go n (c:acc) s



sP = (char 's' +++ char 'S') >> return S
kP = (char 'k' +++ char 'K') >> return K
iP = (char 'i' +++ char 'I') >> return I

runP :: ReadP a -> String -> ([a], String)
runP p s = case readP_to_S p s of
              [] -> ([],[])
              xs -> mapfst (:[]) (last xs)
  where mapfst f (a,b) = (f a,b)
skip :: Int -> ReadP ()
skip n = count n get >> return ()
lexemeP :: ReadP a -> ReadP a
lexemeP p = p >>= \x -> skipSpaces >> return x
nestedP :: (ReadP a -> ReadP a) -> (ReadP a -> ReadP a)
nestedP nest p = p <++ nest (skipSpaces >> nestedP nest p)
parensP  = between oparenP cparenP
bracksP  = between oparenP cparenP
oparenP  = char '('
cparenP  = char ')'
obrackP  = char '['
cbrackP  = char ']'




{-
import Prelude hiding (($))
data Komb = S (Maybe (Komb, Maybe Komb)) | K (Maybe Komb) deriving Show
S Nothing $ x = S (Just (x, Nothing))
S (Just (x, Nothing)) $ y = S (Just (x, Just y))
S (Just (x, Just y)) $ z = x $ z $ (y $ z)
K Nothing $ x = K (Just x)
K (Just x) $ y = y
q x = x $ (c $ k) $ k $ k $ s
 where s = S Nothing
       k = K Nothing
       c = s $ (b $ b $ s) $ k $ k
       b = s $ (k $ s) $ k
-}