fortran-src-0.16.2: src/Language/Fortran/AST/Literal/Boz.hs
{- | Supporting code for handling Fortran BOZ literal constants.
Using the definition from the latest Fortran standards (F2003, F2008), BOZ
constants are bitstrings (untyped!) which have basically no implicit rules. How
they're interpreted depends on context (they are generally limited to DATA
statements and a small handful of intrinsic functions).
Note that currently, we don't store BOZ constants as bitstrings. Storing them in
their string representation is easy and in that form, they're easy to safely
resolve to an integer. An alternate option would be to store them as the
bitstring "B" of BOZ, and only implement functions on that. For simple uses
(integer), I'm doubtful that would provide extra utility or performance, but it
may be more sensible in the future. For now, you may retrieve a bitstring by
converting to a numeric type and using something like 'showIntAtBase', or a
'Bits' instance.
This type carries _some_ syntactic information that doesn't change meaning. The
expectation is that most users won't want to inspect 'Boz' values, usually just
convert them, so we do it for convenience for checking syntax conformance. Note
that not all info is retained -- which of single or double quotes were used is
not recorded, for example.
-}
module Language.Fortran.AST.Literal.Boz where
import GHC.Generics
import Data.Data
import Control.DeepSeq ( NFData )
import Text.PrettyPrint.GenericPretty ( Out )
import qualified Data.List as List
import qualified Data.Char as Char
import qualified Numeric as Num
import Data.Bits
-- | A Fortran BOZ literal constant.
--
-- The prefix defines the characters allowed in the string:
--
-- * @B@: @[01]@
-- * @O@: @[0-7]@
-- * @Z@: @[0-9 a-f A-F]@
data Boz = Boz
{ bozPrefix :: BozPrefix
, bozString :: String
, bozPrefixWasPostfix :: Conforming
-- ^ Was the prefix actually postfix i.e. @'123'z@? This is non-standard
-- syntax, disabled by default in gfortran. Syntactic info.
} deriving stock (Show, Generic, Data, Typeable, Ord)
deriving anyclass (NFData, Out)
-- | Tests prefix & strings match, ignoring conforming/nonconforming flags.
instance Eq Boz where
b1 == b2 = bozPrefix b1 == bozPrefix b2
&& bozString b1 == bozString b2
data BozPrefix
= BozPrefixB -- ^ binary (bitstring)
| BozPrefixO -- ^ octal
| BozPrefixZ Conforming -- ^ hex, including nonstandard @x@
deriving stock (Show, Generic, Data, Typeable, Ord)
deriving anyclass (NFData, Out)
-- | Ignores conforming/nonconforming flags.
instance Eq BozPrefix where
p1 == p2 = case (p1, p2) of (BozPrefixB, BozPrefixB) -> True
(BozPrefixO, BozPrefixO) -> True
(BozPrefixZ{}, BozPrefixZ{}) -> True
_ -> False
data Conforming = Conforming | Nonconforming
deriving stock (Eq, Ord, Show, Generic, Data, Typeable)
deriving anyclass (NFData, Out)
-- | UNSAFE. Parses a BOZ literal constant string.
--
-- Looks for prefix or postfix. Strips the quotes from the string (single quotes
-- only).
parseBoz :: String -> Boz
parseBoz s =
case List.uncons s of
Nothing -> errInvalid
Just (pc, ps) -> case parsePrefix pc of
Just p -> Boz p (shave ps) Conforming
Nothing -> case parsePrefix (List.last s) of
Just p -> Boz p (shave (init s)) Nonconforming
Nothing -> errInvalid
where
parsePrefix p
| p' == 'b' = Just $ BozPrefixB
| p' == 'o' = Just $ BozPrefixO
| p' == 'z' = Just $ BozPrefixZ Conforming
| p' == 'x' = Just $ BozPrefixZ Nonconforming
| otherwise = Nothing
where p' = Char.toLower p
errInvalid = error "Language.Fortran.AST.BOZ.parseBoz: invalid BOZ string"
-- | Remove the first and last elements in a list.
shave = tail . init
-- | Pretty print a BOZ constant. Uses prefix style (ignores the postfix field),
-- and @z@ over nonstandard @x@ for hexadecimal.
prettyBoz :: Boz -> String
prettyBoz b = prettyBozPrefix (bozPrefix b) : '\'' : bozString b <> "'"
where prettyBozPrefix = \case BozPrefixB -> 'b'
BozPrefixO -> 'o'
BozPrefixZ{} -> 'z'
-- | Resolve a BOZ constant as a natural (positive integer).
--
-- Is actually polymorphic over the output type, but you probably want to
-- resolve to 'Integer' or 'Natural' usually.
--
-- We assume the 'Boz' is well-formed, thus don't bother with digit predicates.
bozAsNatural :: (Num a, Eq a) => Boz -> a
bozAsNatural (Boz pfx str _) = runReadS $ parser str
where
runReadS = fst . head
parser = case pfx of BozPrefixB -> Num.readInt 2 (const True) binDigitVal
-- (on GHC >=9.2, 'Num.readBin')
BozPrefixO -> Num.readOct
BozPrefixZ{} -> Num.readHex
binDigitVal = \case '0' -> 0
'1' -> 1
_ -> error "Language.Fortran.AST.BOZ.bozAsNatural: invalid BOZ string"
-- | Resolve a BOZ constant as a two's complement integer.
--
-- Note that the value will depend on the size of the output type.
bozAsTwosComp :: (Num a, Eq a, FiniteBits a) => Boz -> a
bozAsTwosComp boz =
if msbIsSet
then asNat - (2 ^ bitCount)
else asNat
where
msbIsSet = testBit asNat (bitCount - 1)
asNat = bozAsNatural boz
bitCount = finiteBitSize asNat