eigen-1.0.0: Data/Eigen/LA.hs
{-# LANGUAGE RecordWildCards, ForeignFunctionInterface #-}
{- |
The problem: You have a system of equations, that you have written as a single matrix equation
@Ax = b@
Where A and b are matrices (b could be a vector, as a special case). You want to find a solution x.
The solution: You can choose between various decompositions, depending on what your matrix A looks like, and depending on whether you favor speed or accuracy. However, let's start with an example that works in all cases, and is a good compromise:
@
import Data.Eigen.Matrix
import Data.Eigen.LA
main = do
let
a = fromList [[1,2,3], [4,5,6], [7,8,10]]
b = fromList [[3],[3],[4]]
x = solve ColPivHouseholderQR a b
putStrLn \"Here is the matrix A:\" >> print a
putStrLn \"Here is the vector b:\" >> print b
putStrLn \"The solution is:\" >> print x
@
produces the following output
@
Here is the matrix A:
Matrix 3x3
1.0 2.0 3.0
4.0 5.0 6.0
7.0 8.0 10.0
Here is the vector b:
Matrix 3x1
3.0
3.0
4.0
The solution is:
Matrix 3x1
-2.0000000000000004
1.0000000000000018
0.9999999999999989
@
Checking if a solution really exists: Only you know what error margin you want to allow for a solution to be considered valid.
You can compute relative error using @norm (ax - b) / norm b@ formula or use 'relativeError' function which provides the same calculation implemented slightly more efficient.
-}
module Data.Eigen.LA (
-- * Basic linear solving
Decomposition(..),
solve,
relativeError,
-- * Multiple linear regression
linearRegression
) where
import Foreign.Ptr
import Foreign.C.Types
import Foreign.C.String
import Foreign.Storable
import Foreign.Marshal.Alloc
import Data.Eigen.Matrix
import qualified Data.Eigen.Matrix.Mutable as MM
import Data.Eigen.Internal
import System.IO.Unsafe
foreign import ccall "eigen-proxy.h eigen_solve" c_solve :: CInt -> Ptr C_MatrixXd -> Ptr C_MatrixXd -> Ptr C_MatrixXd -> IO CString
foreign import ccall "eigen-proxy.h eigen_relativeError" c_relativeError :: Ptr CDouble -> Ptr C_MatrixXd -> Ptr C_MatrixXd -> Ptr C_MatrixXd -> IO CString
{- |
@
Decomposition Requirements on the matrix Speed Accuracy
PartialPivLU Invertible ++ +
FullPivLU None - +++
HouseholderQR None ++ +
ColPivHouseholderQR None + ++
FullPivHouseholderQR None - +++
LLT Positive definite +++ +
LDLT Positive or negative semidefinite +++ ++
JacobiSVD None - +++
The best way to do least squares solving for square matrices is with a SVD decomposition (JacobiSVD)
@
-}
data Decomposition
-- | LU decomposition of a matrix with partial pivoting.
= PartialPivLU
-- | LU decomposition of a matrix with complete pivoting.
| FullPivLU
-- | Householder QR decomposition of a matrix.
| HouseholderQR
-- | Householder rank-revealing QR decomposition of a matrix with column-pivoting.
| ColPivHouseholderQR
-- | Householder rank-revealing QR decomposition of a matrix with full pivoting.
| FullPivHouseholderQR
-- | Standard Cholesky decomposition (LL^T) of a matrix.
| LLT
-- | Robust Cholesky decomposition of a matrix with pivoting.
| LDLT
-- | Two-sided Jacobi SVD decomposition of a rectangular matrix.
| JacobiSVD deriving (Show, Enum)
-- | [x = solve d a b] finds a solution @x@ of @ax = b@ equation using decomposition @d@
solve :: Decomposition -> Matrix -> Matrix -> Matrix
solve d a b = (`modify` empty) $ \x ->
with a $ \pa ->
with b $ \pb ->
MM.with x $ \px ->
call $ c_solve (fromIntegral $ fromEnum d) px pa pb
-- | [e = relativeError x a b] computes @norm (ax - b) / norm b@ where @norm@ is L2 norm
relativeError :: Matrix -> Matrix -> Matrix -> Double
relativeError x a b = unsafePerformIO $
with x $ \px ->
with a $ \pa ->
with b $ \pb ->
alloca $ \pr -> do
call $ c_relativeError pr px pa pb
fmap cast $ peek pr
{- |
[(coeffs, error) = linearRegression points] computes multiple linear regression @y = a1 x1 + a2 x2 + ... + an xn + b@ using 'ColPivHouseholderQR' decomposition
* point format is @[y, x1..xn]@
* coeffs format is @[b, a1..an]@
* error is calculated using 'relativeError'
@
import Data.Eigen.LA
main = print $ linearRegression [
[-4.32, 3.02, 6.89],
[-3.79, 2.01, 5.39],
[-4.01, 2.41, 6.01],
[-3.86, 2.09, 5.55],
[-4.10, 2.58, 6.32]]
@
produces the following output
@
([-2.3466569233817127,-0.2534897541434826,-0.1749653335680988],1.8905965120153139e-3)
@
-}
linearRegression :: [[Double]] -> ([Double], Double)
linearRegression points = (coeffs, e) where
a = fromList $ map ((1:).tail) points
b = fromList $ map ((:[]).head) points
x = solve ColPivHouseholderQR a b
e = relativeError x a b
coeffs = map head $ toList x