Unique-0.4.3: Data/List/UniqueUnsorted.hs
-----------------------------------------------------------------------------
-- |
-- Module : Data.List.UniqueUnsorted
-- Copyright : (c) Volodymyr Yaschenko
-- License : BSD3
--
-- Maintainer : ualinuxcn@gmail.com
-- Stability : Unstable
-- Portability : portable
--
-- Library provides functions to find unique and duplicate elements in the list.
-- Unlike Unique or UniqueStrict modules this one uses Data.HashMap.Strict for calculation.
--
-- The elements in the list can be unsorted (do not have an instance of Ord class, but Hashable is needed).
-- This implementation is good for ByteStrings.
module Data.List.UniqueUnsorted
( repeated
, repeatedBy
, unique
, count
, count_
)
where
import Data.Hashable
import qualified Data.HashMap.Strict as HS (HashMap, filter, fromListWith, keys,
toList)
import qualified Data.IntMap.Strict as IM (fromListWith, toList)
countMap :: (Hashable a, Eq a) => [a] -> HS.HashMap a Int
countMap = HS.fromListWith (+) . flip zip (repeat 1)
-- | The 'repeatedBy' function behaves just like 'repeated', except it uses a user-supplied equality predicate.
--
-- > repeatedBy (>2) "This is the test line" == " stei"
repeatedBy :: (Hashable a, Eq a) => (Int -> Bool) -> [a] -> [a]
repeatedBy p = HS.keys . HS.filter p . countMap
-- | 'repeated' finds only the elements that are present more than once in the list. Example:
--
-- > repeated "foo bar" == "o"
repeated :: (Hashable a, Eq a) => [a] -> [a]
repeated = repeatedBy (>1)
-- | 'unique' gets only unique elements, that do not have duplicates.
--
-- > unique "foo bar" == " abrf"
unique :: (Hashable a, Eq a) => [a] -> [a]
unique = repeatedBy (==1)
-- | 'count' of each element in the list. Example:
--
-- > count "This is the test line" == [(' ',4),('s',3),('T',1),('t',3),('e',3),('h',2),('i',3),('l',1),('n',1)]
count :: (Hashable a, Eq a) => [a] -> [(a, Int)]
count = HS.toList . countMap
-- | 'count_' of each elements in the list, it sorts by their number. Example:
--
-- > count_ "This is the test line" == [('n',1),('l',1),('T',1),('h',2),('i',3),('e',3),('t',3),('s',3),(' ',4)]
count_ :: (Hashable a, Eq a) => [a] -> [(a, Int)]
count_ = fromIntMap . toIntMap . HS.toList . countMap
where toIntMap = IM.fromListWith (++) . map (\(x,y) -> (y,[x]))
fromIntMap = concatMap (\(x,y) -> zip y $ repeat x) . IM.toList