diff --git a/CHANGELOG.md b/CHANGELOG.md
new file mode 100644
--- /dev/null
+++ b/CHANGELOG.md
@@ -0,0 +1,4 @@
+# Changes in version 0.2.0.0
+  * Move `Data.Algorithm.Patience` to `Patience`
+  * Remove use of deprecated `Data.Map.insertWith'`
+  * Add strictness/UNPACK annotations to `Int` values
diff --git a/Data/Algorithm/Patience.hs b/Data/Algorithm/Patience.hs
deleted file mode 100644
--- a/Data/Algorithm/Patience.hs
+++ /dev/null
@@ -1,154 +0,0 @@
-{-# LANGUAGE
-    DeriveDataTypeable
-  , ViewPatterns
-  , CPP #-}
--- | Implements \"patience diff\" and the patience algorithm for the longest
---   increasing subsequence problem.
-module Data.Algorithm.Patience
-  ( -- * Patience diff
-    diff
-  , Item(..), itemChar, itemValue
-    -- * Longest increasing subsequence
-  , longestIncreasing
-  ) where
-import qualified Data.Sequence as S
-import Data.Sequence ( (<|), (|>), (><), ViewL(..), ViewR(..) )
-import qualified Data.Foldable as F
-import qualified Data.Map      as M
-import qualified Data.IntMap   as IM
-
-import Data.List
-import Data.Ord
-
-import Data.Typeable ( Typeable )
-import Data.Data     ( Data     )
-
--- If key xi is in the map, move it to xf while adjusting the value with f.
-adjMove :: (a -> a) -> Int -> Int -> IM.IntMap a -> IM.IntMap a
-adjMove f xi xf m = case IM.updateLookupWithKey (\_ _ -> Nothing) xi m of
-  (Just v, mm) -> IM.insert xf (f v) mm
-  (Nothing, _) -> m
-
--- A "card" is an integer value (with annotation) plus a "backpointer" to
--- a card in the previous pile, if any.
-data Card a = Card Int a (Maybe (Card a))
-
--- | Given: a list of distinct integers.  Picks a subset of the integers
---   in the same order, i.e. a subsequence, with the property that
---
---   * it is monotonically increasing, and
---
---   * it is at least as long as any other such subsequence.
---
--- This function uses patience sort:
--- <http://en.wikipedia.org/wiki/Patience_sorting>.
--- For implementation reasons, the actual list returned is the reverse of
--- the subsequence.
---
--- You can pair each integer with an arbitrary annotation, which will be
--- carried through the algorithm.
-longestIncreasing :: [(Int,a)] -> [(Int,a)]
-longestIncreasing = extract . foldl' ins IM.empty where
-  -- Insert a card into the proper pile.
-  -- type Pile  a = [Card a]
-  -- type Piles a = IM.IntMap (Pile a)  -- keyed by smallest element
-  ins m (x,a) =
-    let (lt, gt) = IM.split x m
-        prev = (head . fst) `fmap` IM.maxView lt
-        new  = Card x a prev
-    in case IM.minViewWithKey gt of
-      Nothing        -> IM.insert x [new] m   -- new pile
-      Just ((k,_),_) -> adjMove (new:) k x m  -- top of old pile
-  -- Walk the backpointers, starting at the top card of the
-  -- highest-keyed pile.
-  extract (IM.maxView -> Just (c,_)) = walk $ head c
-  extract _ = []
-  walk (Card x a c) = (x,a) : maybe [] walk c
-
--- Elements whose second component appears exactly once.
-unique :: (Ord t) => S.Seq (a,t) -> M.Map t a
-unique = M.mapMaybe id . F.foldr ins M.empty where
-  ins (a,x) = M.insertWith' (\_ _ -> Nothing) x (Just a)
-
--- Given two sequences of numbered "lines", returns a list of points
--- where unique lines match up.
-solveLCS :: (Ord t) => S.Seq (Int,t) -> S.Seq (Int,t) -> [(Int,Int)]
-solveLCS ma mb =
-  let xs = M.elems $ M.intersectionWith (,) (unique ma) (unique mb)
-  in  longestIncreasing $ sortBy (comparing snd) xs
-
--- Type for decomposing a diff problem.  We either have two
--- lines that match, or a recursive subproblem.
-data Piece a
-  = Match a a
-  | Diff (S.Seq a) (S.Seq a)
-  deriving (Show)
-
--- Subdivides a diff problem according to the indices of matching lines.
-chop :: S.Seq t -> S.Seq t -> [(Int,Int)] -> [Piece t]
-chop xs ys []
-  | S.null xs && S.null ys = []
-  | otherwise = [Diff xs ys]
-chop xs ys ((nx,ny):ns) =
-  let (xsr, S.viewl -> (x :< xse)) = S.splitAt nx xs
-      (ysr, S.viewl -> (y :< yse)) = S.splitAt ny ys
-  in  Diff xse yse : Match x y : chop xsr ysr ns
-
--- Zip a list with a Seq.
-zipLS :: [a] -> S.Seq b -> S.Seq (a, b)
-#if MIN_VERSION_containers(0,3,0)
-zipLS = S.zip . S.fromList
-#else
-zipLS xs = S.fromList . zip xs . F.toList
-#endif
-
--- Number the elements of a Seq.
-number :: S.Seq t -> S.Seq (Int,t)
-number xs = zipLS [0..S.length xs - 1] xs
-
--- | An element of a computed difference.
-data Item t
-  = Old  t    -- ^ Value taken from the \"old\" list, i.e. left argument to 'diff'
-  | New  t    -- ^ Value taken from the \"new\" list, i.e. right argument to 'diff'
-  | Both t t  -- ^ Value taken from both lists.  Both values are provided, in case
-              --   your type has a non-structural definition of equality.
-  deriving (Eq, Ord, Show, Read, Typeable, Data)
-
-instance Functor Item where
-  fmap f (Old  x  ) = Old  (f x)
-  fmap f (New  x  ) = New  (f x)
-  fmap f (Both x y) = Both (f x) (f y)
-
--- | The difference between two lists, according to the
--- \"patience diff\" algorithm.
-diff :: (Ord t) => [t] -> [t] -> [Item t]
-diff xsl ysl = F.toList $ go (S.fromList xsl) (S.fromList ysl) where
-  -- Handle common elements at the beginning / end.
-  go (S.viewl -> (x :< xs)) (S.viewl -> (y :< ys))
-    | x == y = Both x y <| go xs ys
-  go (S.viewr -> (xs :> x)) (S.viewr -> (ys :> y))
-    | x == y = go xs ys |> Both x y
-  -- Find an increasing sequence of matching unique lines, then
-  -- subdivide at those points and recurse.
-  go xs ys = case chop xs ys $ solveLCS (number xs) (number ys) of
-    -- If we fail to subdivide, just record the chunk as is.
-    [Diff _ _] -> fmap Old xs >< fmap New ys
-    ps -> recur ps
-
-  -- Apply the algorithm recursively to a decomposed problem.
-  -- The decomposition list is in reversed order.
-  recur [] = S.empty
-  recur (Match x y  : ps) = recur ps |> Both x y
-  recur (Diff xs ys : ps) = recur ps >< go xs ys
-
--- | The character @\'-\'@ or @\'+\'@ or @\' \'@ for 'Old' or 'New' or 'Both' respectively.
-itemChar :: Item t -> Char
-itemChar (Old  _  ) = '-'
-itemChar (New  _  ) = '+'
-itemChar (Both _ _) = ' '
-
--- | The value from an 'Item'.  For 'Both', returns the \"old\" value.
-itemValue :: Item t -> t
-itemValue (Old  x  ) = x
-itemValue (New  x  ) = x
-itemValue (Both x _) = x
diff --git a/README.md b/README.md
new file mode 100644
--- /dev/null
+++ b/README.md
@@ -0,0 +1,15 @@
+[![Hackage](https://img.shields.io/hackage/v/patience.svg)](https://hackage.haskell.org/package/patience)
+
+# patience
+
+## About
+This library implements the "patience diff" algorithm, as well as the patience algorithm for the
+longest increasing subsequence problem.
+
+Patience diff computes the difference between two lists, for example the lines of two versions of
+a source file. It provides a good balance of performance, nice output for humans, and implementation
+simplicity. For more information, see these two blog posts: [alfedenzo](http://alfedenzo.livejournal.com/170301.html), [bramcohen](http://bramcohen.livejournal.com/73318.html)
+
+## Install
+
+Install with `cabal (new-)install patience`.
diff --git a/patience.cabal b/patience.cabal
--- a/patience.cabal
+++ b/patience.cabal
@@ -1,13 +1,14 @@
-name:                patience
-version:             0.1.1
-license:             BSD3
-license-file:        LICENSE
-synopsis:            Patience diff and longest increasing subsequence
-category:            Algorithms, Text
-author:              Keegan McAllister <mcallister.keegan@gmail.com>
-maintainer:          Keegan McAllister <mcallister.keegan@gmail.com>
-build-type:          Simple
-cabal-version:       >=1.2
+cabal-version: 2.2
+name:
+  patience
+version:
+  0.2.0.0
+license:
+  BSD-3-Clause
+license-file:
+  LICENSE
+synopsis:
+  Patience diff and longest increasing subsequence
 description:
   This library implements the \"patience diff\" algorithm, as well as the patience
   algorithm for the longest increasing subsequence problem.
@@ -17,16 +18,27 @@
   performance, nice output for humans, and implementation simplicity.  For more
   information, see <http://alfedenzo.livejournal.com/170301.html> and
   <http://bramcohen.livejournal.com/73318.html>.
-  .
-  New in version 0.1.1: relaxed @containers@ dependency, so it should build on
-  GHC 6.10.
-
+category:
+  Algorithms, Text
+author:
+  Keegan McAllister <mcallister.keegan@gmail.com>
+maintainer:
+  chessai <chessai1996@gmail.com> 
+build-type:
+  Simple
 extra-source-files:
-  test/test.hs
+  CHANGELOG.md
+  README.md
 
 library
-  exposed-modules:  Data.Algorithm.Patience
-  ghc-options:      -Wall
+  hs-source-dirs:
+    src
+  exposed-modules:
+    Patience
+  ghc-options:
+    -Wall
+  default-language:
+    Haskell2010
   build-depends:
-      base >= 3 && < 5
-    , containers >= 0.2
+      base >= 4.3 && < 5
+    , containers >= 0.5.9 && < 0.7
diff --git a/src/Patience.hs b/src/Patience.hs
new file mode 100644
--- /dev/null
+++ b/src/Patience.hs
@@ -0,0 +1,155 @@
+{-# LANGUAGE BangPatterns       #-}
+{-# LANGUAGE CPP                #-}
+{-# LANGUAGE DeriveDataTypeable #-}
+{-# LANGUAGE ViewPatterns       #-}
+
+-- | Implements \"patience diff\" and the patience algorithm for the longest
+--   increasing subsequence problem.
+module Patience
+  ( -- * Patience diff
+    diff
+  , Item(..), itemChar, itemValue
+    -- * Longest increasing subsequence
+  , longestIncreasing
+  ) where
+
+import           Data.Data       (Data)
+import qualified Data.Foldable   as F
+import qualified Data.IntMap     as IM
+import           Data.List
+import qualified Data.Map        as M
+import qualified Data.Map.Strict as MS
+import           Data.Ord
+import           Data.Sequence   ( (<|), (|>), (><), ViewL(..), ViewR(..) )
+import qualified Data.Sequence   as S
+import           Data.Typeable   (Typeable)
+
+-- If key xi is in the map, move it to xf while adjusting the value with f.
+adjMove :: (a -> a) -> Int -> Int -> IM.IntMap a -> IM.IntMap a
+adjMove f !xi !xf m = case IM.updateLookupWithKey (\_ _ -> Nothing) xi m of
+  (Just v, mm) -> IM.insert xf (f v) mm
+  (Nothing, _) -> m
+
+-- A "card" is an integer value (with annotation) plus a "backpointer" to
+-- a card in the previous pile, if any.
+data Card a = Card {-# UNPACK #-} !Int a (Maybe (Card a))
+
+-- | Given: a list of distinct integers.  Picks a subset of the integers
+--   in the same order, i.e. a subsequence, with the property that
+--
+--   * it is monotonically increasing, and
+--
+--   * it is at least as long as any other such subsequence.
+--
+-- This function uses patience sort:
+-- <http://en.wikipedia.org/wiki/Patience_sorting>.
+-- For implementation reasons, the actual list returned is the reverse of
+-- the subsequence.
+--
+-- You can pair each integer with an arbitrary annotation, which will be
+-- carried through the algorithm.
+longestIncreasing :: [(Int,a)] -> [(Int,a)]
+longestIncreasing = extract . F.foldl' ins IM.empty where
+  -- Insert a card into the proper pile.
+  -- type Pile  a = [Card a]
+  -- type Piles a = IM.IntMap (Pile a)  -- keyed by smallest element
+  ins m (x,a) =
+    let (lt, gt) = IM.split x m
+        prev = (head . fst) `fmap` IM.maxView lt
+        new  = Card x a prev
+    in case IM.minViewWithKey gt of
+      Nothing        -> IM.insert x [new] m   -- new pile
+      Just ((k,_),_) -> adjMove (new:) k x m  -- top of old pile
+  -- Walk the backpointers, starting at the top card of the
+  -- highest-keyed pile.
+  extract (IM.maxView -> Just (c,_)) = walk $ head c
+  extract _ = []
+  walk (Card x a c) = (x,a) : maybe [] walk c
+
+-- Elements whose second component appears exactly once.
+unique :: (Ord t) => S.Seq (a,t) -> M.Map t a
+unique = M.mapMaybe id . F.foldr ins M.empty where
+  ins (a,x) = MS.insertWith (\_ _ -> Nothing) x (Just a)
+
+-- Given two sequences of numbered "lines", returns a list of points
+-- where unique lines match up.
+solveLCS :: (Ord t) => S.Seq (Int,t) -> S.Seq (Int,t) -> [(Int,Int)]
+solveLCS ma mb =
+  let xs = M.elems $ M.intersectionWith (,) (unique ma) (unique mb)
+  in  longestIncreasing $ sortBy (comparing snd) xs
+
+-- Type for decomposing a diff problem.  We either have two
+-- lines that match, or a recursive subproblem.
+data Piece a
+  = Match a a
+  | Diff (S.Seq a) (S.Seq a)
+  deriving (Show)
+
+-- Subdivides a diff problem according to the indices of matching lines.
+chop :: S.Seq t -> S.Seq t -> [(Int,Int)] -> [Piece t]
+chop xs ys []
+  | S.null xs && S.null ys = []
+  | otherwise = [Diff xs ys]
+chop xs ys (!(!nx,!ny):ns) =
+  let (xsr, S.viewl -> (x :< xse)) = S.splitAt nx xs
+      (ysr, S.viewl -> (y :< yse)) = S.splitAt ny ys
+  in  Diff xse yse : Match x y : chop xsr ysr ns
+
+-- Zip a list with a Seq.
+zipLS :: [a] -> S.Seq b -> S.Seq (a, b)
+#if MIN_VERSION_containers(0,3,0)
+zipLS = S.zip . S.fromList
+#else
+zipLS xs = S.fromList . zip xs . F.toList
+#endif
+
+-- Number the elements of a Seq.
+number :: S.Seq t -> S.Seq (Int,t)
+number xs = zipLS [0..S.length xs - 1] xs
+
+-- | An element of a computed difference.
+data Item t
+  = Old  t    -- ^ Value taken from the \"old\" list, i.e. left argument to 'diff'
+  | New  t    -- ^ Value taken from the \"new\" list, i.e. right argument to 'diff'
+  | Both t t  -- ^ Value taken from both lists.  Both values are provided, in case
+              --   your type has a non-structural definition of equality.
+  deriving (Eq, Ord, Show, Read, Typeable, Data)
+
+instance Functor Item where
+  fmap f (Old  x  ) = Old  (f x)
+  fmap f (New  x  ) = New  (f x)
+  fmap f (Both x y) = Both (f x) (f y)
+
+-- | The difference between two lists, according to the
+-- \"patience diff\" algorithm.
+diff :: (Ord t) => [t] -> [t] -> [Item t]
+diff xsl ysl = F.toList $ go (S.fromList xsl) (S.fromList ysl) where
+  -- Handle common elements at the beginning / end.
+  go (S.viewl -> (x :< xs)) (S.viewl -> (y :< ys))
+    | x == y = Both x y <| go xs ys
+  go (S.viewr -> (xs :> x)) (S.viewr -> (ys :> y))
+    | x == y = go xs ys |> Both x y
+  -- Find an increasing sequence of matching unique lines, then
+  -- subdivide at those points and recurse.
+  go xs ys = case chop xs ys $ solveLCS (number xs) (number ys) of
+    -- If we fail to subdivide, just record the chunk as is.
+    [Diff _ _] -> fmap Old xs >< fmap New ys
+    ps -> recur ps
+
+  -- Apply the algorithm recursively to a decomposed problem.
+  -- The decomposition list is in reversed order.
+  recur [] = S.empty
+  recur (Match x y  : ps) = recur ps |> Both x y
+  recur (Diff xs ys : ps) = recur ps >< go xs ys
+
+-- | The character @\'-\'@ or @\'+\'@ or @\' \'@ for 'Old' or 'New' or 'Both' respectively.
+itemChar :: Item t -> Char
+itemChar (Old  _  ) = '-'
+itemChar (New  _  ) = '+'
+itemChar (Both _ _) = ' '
+
+-- | The value from an 'Item'.  For 'Both', returns the \"old\" value.
+itemValue :: Item t -> t
+itemValue (Old  x  ) = x
+itemValue (New  x  ) = x
+itemValue (Both x _) = x
diff --git a/test/test.hs b/test/test.hs
deleted file mode 100644
--- a/test/test.hs
+++ /dev/null
@@ -1,45 +0,0 @@
--- Simple test for Data.Algorithm.Patience
---
--- Invoke as: ./test r n
--- for ints r, n
---
--- Reads lines of standard input, then repeats r times:
---   - Generate two documents of n lines each, by picking
---     randomly from the stdin lines, with replacement
---   - Compute their patience diff
---   - Check that each document is recovered by keeping the
---     respective side of the diff
-module Main(main) where
-
-import Control.Monad
-import Data.Array
-import Data.Maybe
-import System.Environment
-import System.Random
-
-import Data.Algorithm.Patience
-
-keepOld :: [Item a] -> [a]
-keepOld = catMaybes . map f where
-  f (Old  x  ) = Just x
-  f (New    _) = Nothing
-  f (Both x _) = Just x
-
-keepNew :: [Item a] -> [a]
-keepNew = catMaybes . map f where
-  f (Old  _  ) = Nothing
-  f (New    x) = Just x
-  f (Both _ x) = Just x
-
-main :: IO ()
-main = do
-  [r,n] <- map read `fmap` getArgs
-  xs    <- lines `fmap` getContents
-  let ar   = listArray (0, length xs - 1) xs
-      pick = replicateM n ((ar !) `fmap` randomRIO (bounds ar))
-  replicateM_ r $ do
-    da <- pick
-    db <- pick
-    let d    = diff da db
-        good = (da == keepOld d) && (db == keepNew d)
-    when (not good) $ print (da, db, d)
